1. (a) Mercury, Mars, Venus, Earth

All
four correct – 1 mark 1

(b) (i) A calculation to include:

1. (60 x 9.8 =) 588;

2. N; 2

2. N; 2

(ii) Mercury and Mars; (either order) 1

(c) An
explanation to include:

1. Venus; 2. it has the greatest atmospheric
pressure; [Do
not accept more than one answer] 2

(d) An
explanation to include:

1.
hotter;

2. other planets are colder the further from the Sun;

[Ignore explanations of why] 2

2. other planets are colder the further from the Sun;

[Ignore explanations of why] 2

2. (a) (i) 5
(N); 1

(ii) forces
balanced / cancel / equal / book not moving /

no unbalanced force / no resultant force; 1

no unbalanced force / no resultant force; 1

(b) (i) air resistance / drag / air
friction; 1

[ignore upthrust]

[ignore upthrust]

(ii) W
– R / 5 – R 1

3. (a) points
plotted correctly;; [Deduct 1 mark for each error] 2

[Line not necessary]

[Line not necessary]

(b) 3 (m/s); 1

(c) (i) acceleration
= change
in velocity/ time taken; 1

[Accept a = (v-u)/t]

[Accept a = (v-u)/t]

(ii) acceleration = 3/15;
[Allow
ecf from
part (b)]

= 0.2 (m/s2); 2

= 0.2 (m/s2); 2

4. (a) drag/resistance/force/push/thrust/upthrust;

air/atmosphere; [Reject wind/friction] 2

air/atmosphere; [Reject wind/friction] 2

(b) 56; 1

(c) (i) pull of Earth/weight/gravitational
pull/downward (pull) greater than upward (push)/there is resultant force
downwards; [Allow
gravity] 1

(ii) both forces the same/
balanced/ equal/ resultant force is zero/
OWTTE; 1

(d) (i) speed decreases; new lower
terminal velocity/horizontal region
shown; 2

(ii) An explanation to include three from:

air
resistance
increases;
at start
upward force greater than downward force;
eventually forces
balance;
larger surface
area;
air resistance
decreases as parachutist slows down; 3

5.(a) A calculation to include: =½
x1000 x 225;;

= 112 500 (J); [bald correct answer, 3 marks]

[If wrong answer look for:

= 112 500 (J); [bald correct answer, 3 marks]

[If wrong answer look for:

either½
x 1000 x152;

or ½ x 1000 x 15;] 3

or ½ x 1000 x 15;] 3

(b) A calculation to show:

Fs (work done) = change in KE = ½
mv2/OWTTE;

F
x 19 =
112 500; [Allow ecf from
part (i)]

F =
5921 (nearly 6000 N);

[bald
correct answer – 1 mark]

5 (c) An
explanation to include four from:

KE
more
than doubled;

KE
proportional to v2/= ½ mv2;

braking
distance
more than doubled;

depends
on v2/KE;

thinking
distance
doubled;

constant
braking
force; 4

(d) An explanation to include:

increase
mass; KE increases;

[Accept
answer in terms of F = ma] 2

6. (a) 0 – 2 (seconds); 1

(b) upwards;

lift is slowing (even though it is falling); 2

[Direction must be mentioned to score second marking point]

lift is slowing (even though it is falling); 2

[Direction must be mentioned to score second marking point]

7. (i) at a greater height; 1

(ii) work done = force(weight) x distance (height) (w
= fd) 1

(iii) 550 × 45 = 24750 J or 24.75 kJ Accept joules/kilojoules

Substitution = 1; Calc and unit = 1; 2

Substitution = 1; Calc and unit = 1; 2

(iv) a=
(v-u)/t

Accept
acceleration = change in velocity/time taken

v = 3 ×
10 = 30
m/s

equation; substitution; calculation and
unit; 3

(v)

__kinetic__1
8. (a) force
=350 N;
direction is
upwards; 2

(b) acceleration = force/mass
= 350/765

= 0.46
m/s2 ; 3

(c) An explanation to
include:

acceleration decreases; resistive force increases; reducing the size of the unbalanced force; plus 1 communication mark for ensuring that spelling, punctuation

and grammar are accurate, so that the meaning is clear

acceleration decreases; resistive force increases; reducing the size of the unbalanced force; plus 1 communication mark for ensuring that spelling, punctuation

and grammar are accurate, so that the meaning is clear

(d) An explanation to include:

mass / downwards force decreases;

causing an increase in acceleration; 2

mass / downwards force decreases;

causing an increase in acceleration; 2