1. (a) Mercury, Mars, Venus, Earth
All
four correct – 1 mark 1
(b) (i) A calculation to include:
1. (60 x 9.8 =) 588;
2. N; 2
2. N; 2
(ii) Mercury and Mars; (either order) 1
(c) An
explanation to include:
1. Venus; 2. it has the greatest atmospheric
pressure; [Do
not accept more than one answer] 2
(d) An
explanation to include:
1.
hotter;
2. other planets are colder the further from the Sun;
[Ignore explanations of why] 2
2. other planets are colder the further from the Sun;
[Ignore explanations of why] 2
2. (a) (i) 5
(N); 1
(ii) forces
balanced / cancel / equal / book not moving /
no unbalanced force / no resultant force; 1
no unbalanced force / no resultant force; 1
(b) (i) air resistance / drag / air
friction; 1
[ignore upthrust]
[ignore upthrust]
(ii) W
– R / 5 – R 1
3. (a) points
plotted correctly;; [Deduct 1 mark for each error] 2
[Line not necessary]
[Line not necessary]
(b) 3 (m/s); 1
(c) (i) acceleration
= change
in velocity/ time taken; 1
[Accept a = (v-u)/t]
[Accept a = (v-u)/t]
(ii) acceleration = 3/15;
[Allow
ecf from
part (b)]
= 0.2 (m/s2); 2
= 0.2 (m/s2); 2
4. (a) drag/resistance/force/push/thrust/upthrust;
air/atmosphere; [Reject wind/friction] 2
air/atmosphere; [Reject wind/friction] 2
(b) 56; 1
(c) (i) pull of Earth/weight/gravitational
pull/downward (pull) greater than upward (push)/there is resultant force
downwards; [Allow
gravity] 1
(ii) both forces the same/
balanced/ equal/ resultant force is zero/
OWTTE; 1
(d) (i) speed decreases; new lower
terminal velocity/horizontal region
shown; 2
(ii) An explanation to include three from:
air
resistance
increases;
at start
upward force greater than downward force;
eventually forces
balance;
larger surface
area;
air resistance
decreases as parachutist slows down; 3
5.(a) A calculation to include: =½
x1000 x 225;;
= 112 500 (J); [bald correct answer, 3 marks]
[If wrong answer look for:
= 112 500 (J); [bald correct answer, 3 marks]
[If wrong answer look for:
either½
x 1000 x152;
or ½ x 1000 x 15;] 3
or ½ x 1000 x 15;] 3
(b) A calculation to show:
Fs (work done) = change in KE = ½
mv2/OWTTE;
F
x 19 =
112 500; [Allow ecf from
part (i)]
F =
5921 (nearly 6000 N);
[bald
correct answer – 1 mark]
5 (c) An
explanation to include four from:
KE
more
than doubled;
KE
proportional to v2/= ½ mv2;
braking
distance
more than doubled;
depends
on v2/KE;
thinking
distance
doubled;
constant
braking
force; 4
(d) An explanation to include:
increase
mass; KE increases;
[Accept
answer in terms of F = ma] 2
6. (a) 0 – 2 (seconds); 1
(b) upwards;
lift is slowing (even though it is falling); 2
[Direction must be mentioned to score second marking point]
lift is slowing (even though it is falling); 2
[Direction must be mentioned to score second marking point]
7. (i) at a greater height; 1
(ii) work done = force(weight) x distance (height) (w
= fd) 1
(iii) 550 × 45 = 24750 J or 24.75 kJ Accept joules/kilojoules
Substitution = 1; Calc and unit = 1; 2
Substitution = 1; Calc and unit = 1; 2
(iv) a=
(v-u)/t
Accept
acceleration = change in velocity/time taken
v = 3 ×
10 = 30
m/s
equation; substitution; calculation and
unit; 3
(v) kinetic 1
8. (a) force
=350 N;
direction is
upwards; 2
(b) acceleration = force/mass
= 350/765
= 0.46
m/s2 ; 3
(c) An explanation to
include:
acceleration decreases; resistive force increases; reducing the size of the unbalanced force; plus 1 communication mark for ensuring that spelling, punctuation
and grammar are accurate, so that the meaning is clear
acceleration decreases; resistive force increases; reducing the size of the unbalanced force; plus 1 communication mark for ensuring that spelling, punctuation
and grammar are accurate, so that the meaning is clear
(d) An explanation to include:
mass / downwards force decreases;
causing an increase in acceleration; 2
mass / downwards force decreases;
causing an increase in acceleration; 2